仅当 cookie 存在时如何获取 URL 否则重定向到不同的 url？

Question

A cookie has been created in EJS file named click=click11. I want whenever someone goes to url first check whether the cookie is there or not. If its there render a page if it isn't there render different page.

Here is my code. Which I want to render if the cookie exists. Else send error? How to implement?

router.get('/:uuid_d', async (req, res) => {
 const file = await File.findOne({});
 const user = await User.findOne({});
 if(!file) {
      return res.render('download'});
 }

 const response = await file.save();
 const response2 = await user.save();
 const filePath = `${__dirname}/../${file.path}`;

res.download(filePath);
});

Answer 1

in NodeJs in order to get the cookies you have to set

      const cookieParser = require('cookie-parser') 
      app.use(cookieParser())

to Get the cookie

      router.get('/:uuid_d', async (req, res) => {
        const cookies = req.cookies
        const SpecifiedCookie = req.cookies.YourCookieName
         //check if cookie exists
         if(SpecifiedCookie) console.log('true') 
      }