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从未传递到 __init__ 方法的 class 继承属性

[英]Inherit attribute from class that is isn't passed into __init__ method

Ok, so let's say I'm making a class and a child class like this:好的,假设我正在制作一个 class 和一个孩子 class ,如下所示:

class A:
    def __init__(self, list1=[], list2=[]):
        self.list1 = []
        self.list2 = []

class B(A):
    def __init__(self, list2=[]):
       super().__init__(list2)

But, is there a way to implement it like this但是,有没有办法像这样实现它

class A:
    def __init__(self):
        self.list1 = []
        self.list2 = []

class B(A):
    # code here to inherit list1 or list2 from class A

Basically, a way to implement it so the user can't give a value for list1 and list2 (they'd be initialized as empty lists and the user can add elements later with some method) and have class B inherit a list from class A基本上,一种实现它的方法,因此用户不能为 list1 和 list2 提供值(它们将被初始化为空列表,用户可以稍后使用某种方法添加元素)并让 class B 从 class A 继承一个列表

I feel like there is a way to do this other than my workaround, but maybe not because it's a really specific problem我觉得除了我的解决方法之外还有其他方法可以做到这一点,但可能不是因为这是一个非常具体的问题

The code you provided already does what you want it to do.您提供的代码已经完成了您希望它执行的操作。

class A:
    def __init__(self):
        self.list1 = []
        self.list2 = []

class B(A):
    pass

b = B()

print(b.list1)  # prints []

When you inherit a class, you inherit all of its methods, including __init__ .当你继承 class 时,你继承了它的所有方法,包括__init__ Therefore, A.__init__ is (implicitly) called when initializing B .因此,在初始化B时(隐式)调用A.__init__ It's roughly equivalent to大致相当于

class A:
    def __init__(self):
        self.list1 = []
        self.list2 = []

class B(A):
    def __init__(self):
        super().__init__()

which means (almost) the same thing.这意味着(几乎)相同的事情。 You would never do this just to be more explicit;你永远不会为了更明确而这样做; you would only do it if you wanted to add behavior to B.__init__ that A.__init__ shouldn't have.如果您想向B.__init__添加A.__init__不应该有的行为,您只会这样做。

Your code already does what you want:您的代码已经完成了您想要的操作:

class A:
    def __init__(self):
        self.list1 = []
        self.list2 = []

class B(A):
    # code here to inherit list1 or list2 from class A
    def __init__(self):
        super().__init__() # <- This calls class A init function which creates the two empty lists

Your code does nothing with the user-provided lists.您的代码对用户提供的列表没有任何作用。 I think you meant this:我想你的意思是:

class A:
    def __init__(self, list1=[], list2=[]):
        self.list1 = list1
        self.list2 = list2

class B(A):
    def __init__(self, list2=[]):
       super().__init__(list2=list2)

And if you want to inherit the lists in class B from class A, your code has to be as follows:如果你想从 class A 继承 class B 中的列表,你的代码必须如下:

class A:
    def __init__(self):
        self.list1 = []
        self.list2 = []

class B(A):
    pass

And for modification of the lists, provide a setter function:对于列表的修改,提供一个设置器function:

class A:
    def __init__(self):
        self.list1 = []
        self.list2 = []
    def set_list1(list):
        self.list1 = list
    def set_list2(list):
        self.list2 = list

class B(A):
    pass

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