jq slurp 并添加键/值对

Question

$DATA is a long string containing some Email addresses.

echo "$DATA" | grep -Eo "\b[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,6}\b" | sort | uniq | jq --slurp --raw-input 'split("\n")[:-1]'

Output:

[
  "email1@mydomain.com",
  "email2@mydomain.com",
  "email3@mydomain.com",
  "email4@mydomain.com"
]

Desired Output:

[
  {
    "email": "email1@mydomain.com",
    "free": "0",
    "used": "0"
  },
  {
    "email": "email2@mydomain.com",
    "free": "0",
    "used": "0"
  },
  {
    "email": "email3@mydomain.com",
    "free": "0",
    "used": "0"
  },
  {
    "email": "email4@mydomain.com",
    "free": "0",
    "used": "0"
  }
]

I guess it should be something like += {"free": "0"}

Answer 1

You can replace your current jq command by the following:

jq --slurp --raw-input 'split("\n")[:-1] | map({email: ., free: 0, used: 0})'

You can try it here .