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如何将浮点数四舍五入到小数点后三位?

[英]How to round float down to 3 decimal places?

I wrote a function to return the energy of a given wavelength.我写了一个 function 来返回给定波长的能量。 When I run the function the print statement returns the float E , but returns 20+ decimals and I cannot figure out how to round it down.当我运行 function 时,打印语句返回 float E ,但返回 20+ 位小数,我不知道如何将其四舍五入。

def FindWaveEnergy(color, lam):
  c = 3.0E8
  V = c/lam
  h = 6.626E-34
  E = h*V
  print("The energy of the " + color.lower() + " wave is " + str(E) + "J.")
FindWaveEnergy("red", 6.60E-7)

I tried doing this:我试过这样做:

def FindWaveEnergy(color, lam):
  c = 3.0E8
  V = c/lam
  h = 6.626E-34
  E = h*V
  print("The energy of the " + color.lower() + " wave is " + str('{:.2f}'.format(E)) + "J.")
FindWaveEnergy("red", 6.60E-7)

But that returned 0.000000J .但这返回了0.000000J How can I fix my program to return 3 decimal places?如何修复我的程序以返回 3 个小数位?

The program returns an E value.程序返回一个 E 值。 ie 3.10118181818181815e-19J .3.10118181818181815e-19J I want it to return something like 3.1012e-19J with fewer decimal places.我希望它返回类似3.1012e-19J的小数位数更少的内容。

You are actually nearly there.你实际上就快到了。 I found this Question我发现了这个问题

So all you have to do is change所以你所要做的就是改变

str('{:.2f}'.format(E))

to

str('{:.3g}'.format(E))

Try this:尝试这个:

def FindWaveEnergy(color, lam):
  c = 3.0E8
  V = c/lam
  h = 6.626E-34
  E = str(h*V).split("e")
  print("The energy of the " + color.lower() + " wave is " + E[0][:4] + "e" + E[-1] + "J.")
FindWaveEnergy("red", 6.60E-7)

or you can:或者您可以:

print("The energy of the " + color.lower() + " wave is " + str('{:.2e}'.format(E)) + "J.")

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