[英]JDBC: “SQLException:Column name is not found”
I have tried to use these two questions as a reference我试图用这两个问题作为参考
However, none of it helped my case.但是,这对我的情况没有任何帮助。 I keep receiving
java.sql.SQLException: Column 'debut' not found.
我不断收到
java.sql.SQLException: Column 'debut' not found.
this is my SQL这是我的 SQL
private List<MemberModel> getModelFromNickname(String test) throws SQLException {
List<MemberModel> result = new ArrayList<>();
String sql = "select distinct " +
"m.name," +
"m.visual," +
"m.branch, " +
"m.illustrator, " +
"m.debut3D AS debut " +
"FROM " +
"member_list as m, " +
"nickname AS n " +
"WHERE n.nick_id = m.nick AND n.nickname LIKE ?";
ResultSet ret= sqlAdapter.select(
sql, 1,test
);
while (ret.next()){
result.add(fillRecord(ret));
}
return result;
}
this is my MYSQLAdapter这是我的 MYSQLAdapter
public ResultSet select(String sql,int option, Object... params) throws SQLException {
PreparedStatement query;
try{
logger.info(params.length);
query = getConnection().prepareStatement(sql);
}
catch (Exception e){
throw new Error("Problem "+ e);
}
resolveParameters(query,option, params);
return query.executeQuery();
}
this is my fillRecord command这是我的 fillRecord 命令
private static MemberModel fillRecord(ResultSet resultSet) throws SQLException {
MemberModel member = new MemberModel();
member.name =resultSet.getString("name");
member.branch = resultSet.getString("branch");
member.debut_3d = resultSet.getBoolean("debut");
member.visual = resultSet.getString("visual");
member.illustrator = resultSet.getString("illustrator");
return member;
}
while this is my memberModel虽然这是我的 memberModel
public class MemberModel {
public String name = "";
public int social_media = 0;
public int nick = 0;
public String branch = "";
public boolean debut_3d= true;
public String illustrator ="";
public String visual = "";
}
I tried to use我试着用
ResultSetMetaData rsmd = sqlAdapter.getConnection().prepareStatement(sql).getMetaData();
for(int i =1; i<= rsmd.getColumnCount();i++){
System.err.println(rsmd.getColumnCount()+"\n"+rsmd.getColumnName(i));
}
which gives me the following (I don't know how it somehow managed to print more than 5. But, all of it except "debut" can be found)这给了我以下内容(我不知道它是如何设法打印超过 5 个的。但是,除了“debut”之外的所有内容都可以找到)
5
name
5
visual
5
branch
5
illustrator
5
debut
5
name
5
visual
5
branch
5
illustrator
5
debut
This indicates that the debut column should exist yet I still get that exception.这表明首次亮相的专栏应该存在,但我仍然得到那个例外。 Where did I do wrong?
我哪里做错了? I make sure that it is case sensitive just in case.
我确保它区分大小写以防万一。 The data type for "debut" column is boolean in my localhost XAMPP MySQL.
“debut”列的数据类型是我的本地主机 XAMPP MySQL 中的 boolean。 If I erase
member.debut_3d = resultSet.getBoolean("debut");
如果我删除
member.debut_3d = resultSet.getBoolean("debut");
within fillrecord
... Everything works perfectly fine在
fillrecord
内...一切正常
Rather get values by labelName trying column number.而是通过 labelName 尝试列号获取值。
private static MemberModel fillRecord(ResultSet resultSet) throws SQLException {
MemberModel member = new MemberModel();
member.name = resultSet.getString(1);
member.branch = resultSet.getString(3);
member.debut_3d = resultSet.getBoolean(5);
member.visual = resultSet.getString(2);
member.illustrator = resultSet.getString(4);
return member;
}
resultSet.getBoolean("debut3D"); // Instead of "debut"
The column in the database table is called "debut3D".数据库表中的列称为“debut3D”。
BTW you are not closing PreparedStatement and ResultSet.顺便说一句,您没有关闭 PreparedStatement 和 ResultSet。 I would use try-with-resources.
我会使用 try-with-resources。
The column name is " debut3D
" not " debut
", thats why you are getting the error.列名是“首次
debut3D
”而不是“ debut
”,这就是您收到错误的原因。
Update below line with correct column name,使用正确的列名更新下面的行,
member.debut_3d = resultSet.getBoolean("debut3D");
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