我只想用正则表达式替换“”之外的字符

Question

I want to get the result with regular expression

var text = "\"1test2test3\"test123test45test\"67test89\"";

text.replaceAll(/\"(.*)\"/g, "boom");

boom

but I want

var text = "\"1test2test3\"test123test45test\"67test89\"";

text.replaceAll(????, "boom");

"\"1test2test3\"boom123boom45boom\"67test89\"";

Answer 1

You can use

.replace(/("[^"]*")|test/g, (x,y) => y ? y : "boom")

Details :

• ("[^"]*") - Capturing group 1: a " , then any zero or more chars other than a " and then a "
• | - or
• test - a test string.

The (x,y) => y? y: "boom" (x,y) => y? y: "boom" replacement means that whenever Group 1 ( y ) matches, this group value is returned, else (if test is found in all other contexts), boom is returned.

See the JavaScript demo:

 var text = "\"1test2test3\"test123test45test\"67test89\""; console.log(text.replace(/("[^"]*")|test/g, (x,y) => y? y: "boom"));