如何从 FastAPI 中的 UploadFile 获取文件路径？

Question

Basically, I'm trying to create an endpoint to Upload files to S3

async def upload_files(filepath: str, upload_file_list: List[UploadFile] = File(...)):
    for upload_file in upload_file_list:
        abs_file_path = "/manual/path/works" + upload_file.path
        # Replace above line to get absolute file path from UploadFile
        response = s3_client.upload_file(abs_file_path,bucket_name,
                                                   os.path.join(dest_path, upload_file.filename))

Above is my code to upload multiple files to the S3 bucket. s3_client.upload_file() accepts an absolute file path of the file to upload. It's working when I manually put the full path.

This didn't work:

response = s3_client.upload_file(upload_file.filename, bucket_name,
                                                   os.path.join(dest_path, upload_file.filename))

Is there a way to get this absolute path in FastAPI ? Or any alternative with temp_path without copying or writing the file?

If not, then any alternative with boto3 to upload files to S3 using FastAPI

Answer 1

UploadFile uses Python's SpooledTemporaryFile , which is a "file stored in memory", and "is destroyed as soon as it is closed". You can either read the file contents (ie, contents = await file.read()) and then upload these bytes to your server (if it permits), or please take a look at this answer on how to copy the contents of the uploaded file into a NamedTemporaryFile , which, unlike SpooledTemporaryFile, " is guaranteed to have a visible name in the file system" that "can be used to open the file".