如何将 const uint8_t [] 转换为 std::string？

Question

The below code yields an error,

    void emitData(const uint8_t data[], size_t size)
    {
        std::string encodedMessage(data, size);
    }

Error,

no instance of constructor "std::__2::basic_string<_CharT, _Traits, _Allocator>::basic_string [with _CharT=char, _Traits=std::__2::char_traits<char>, _Allocator=std::__2::allocator<char>]" matches the argument list -- argument types are: (const uint8_t *, size_t) 

Answer 1

Use the overloaded constructor that takes two iterators as parameters: the beginning and ending iterator values. Simple pointers will do the trick:

std::string encodedMessage{data, data+size};