NSubstitute DateTime.Now() 如何让 DateTime.Now() 返回不断增加的日期和时间？

Question

I have several unit tests in which we use NSubstitute for the DateTime. In some cases I want to increment the DateTime.Now() by some set amount so that each time it is called, the date and time are incremented a little. Currently I have:

  private int minutesToAdd = 1;
  private DateTime dateToUse = new DateTime(2018, 1, 1, 0, 0, 0);
  DateTime = Substitute.For<IDateTime>();
  DateTime.Now().Returns(dateToUse.AddMinutes(minutesToAdd)).AndDoes(x => minutesToAdd++) ;

This returns 1/1/2/2018 00:01 every time the function is called.
I thought the "AndDoes" would increment the minutesToAdd each time and would increase the time by one minute.
Can I get the DateTime substitute to increment by one minute each time it is called?

Answer 1

There should be an overload of Returns() that accepts a Func<,> , try it:

var DateTime = Substitute.For<IDateTime>();

DateTime.Now().Returns(x =>
{
    var dt = dateToUse.AddMinutes(minutesToAdd);
    minutesToAdd++;
    return dt;
});

note that you could one-line the Returns() , but I always thought that unncessarily using pre or post increments is unreadable:

DateTime.Now().Returns(x => dateToUse.AddMinutes(minutesToAdd++));