Select 其中 field1 或 field2 或 field3 等于电话号码

Question

I am looking at a table with phone1, phone2 and mobile. However the phone strings are not formatted properly.

The phone numbers are basically free text like this:

row1: phone1:19123123123
row2: mobile:+1 912 123 123
row3: phone2:1 912 123 123
row4: mobile:(+1) 912 123 123
row5: phone2:(+1)912-123-123

Is it possible to write a SQL query to find if one of the fields phone1, phone2 or mobile is +19123123123 but it needs to be able to match any one of those free text examples? Thanks

So in the above example, it should return all 5 records be those free text match that phone number and is in one of the 3 fields.

Answer 1

Assuming the only numbers and + in the column are in the phone number, you can use:

where regexp_replace(col, '[^+0-9]', '') = '+19123123123'

This removes everything that is not a + or digit.

Answer 2

you can use Regex to identify phone number pattern or you can just remove all parenthesis and spaces from the both side of the where clause and then compare.

     SELECT * FROM T 
    WHERE REPLACE(REPLACE(REPLACE(phone1, '(',''),')',''),' ','') = '+19123123123'
        OR REPLACE(REPLACE(REPLACE(phone1, '(',''),')',''),' ','') = '19123123123'
        OR REPLACE(REPLACE(REPLACE(phone2, '(',''),')',''),' ','') = '+19123123123'
        OR REPLACE(REPLACE(REPLACE(phone2, '(',''),')',''),' ','') = '19123123123'
        OR REPLACE(REPLACE(REPLACE(mobile, '(',''),')',''),' ','') = '+19123123123'
        OR REPLACE(REPLACE(REPLACE(mobile, '(',''),')',''),' ','') = '19123123123'

Answer 3

As suggested by Juergen, you can strip all non numeric character and compare. If you are on MySQL 8.0+, you can use below code

REGEXP_REPLACE(SUBSTRING_INDEX(column_name, ':', -1),'[^0-9]+',"")

Assumption: Column value is always being separated by colon(:) after mobile/phone/sometext. Here it will take the second part of your string after colon and then strip the non numeric characters