多个分隔符拆分后如何获取分隔符？

Question

I use this phones = value.split(RegExp(r":| |：| |）")); to split my phone numbers, so I got内線, 7+90+21931465 and 070-2193-1465 from内線：7+90+21931465:070-2193-1465 , but I want to show them as 内線： 7+90+21931465 : 070-2193-1465 , how can I get array as内線, ： , 7+90+21931465 , : and 070-2193-1465 ?

Answer 1

  var value = '内線：7+90+21931465:070-2193-1465';
  var regExp = RegExp(r'^(.+)(：|:)(.+)(：|:)(.+)$');

  print(value);
  var match = regExp.firstMatch(value);
  var numGroups = match.groupCount;
  var groups = match.groups(List<int>.generate(numGroups, (i) => i + 1));
  print(groups.toString());

Another way:

  var chesu = value.split(RegExp(r'：|:'))..insert(1, '：')..insert(3, ':');
  print(chesu);

Answer 2

Does this work for you:

void main() {
  final input = "part1:part2;part3%part4";
  
  final result = <String>[];
  
  input.splitMapJoin(
    RegExp(r":|;|%"), 
    onMatch: (match) {
      result.add(match.group(0));
      return "";
    },
    onNonMatch: (value) {
      result.add(value);
      return "";
    },
  );
  
  print(result);
}

Output:

[part1, :, part2, ;, part3, %, part4]