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查找多维数组中的每个子数组,如果固定 position 上的元素是该子数组的最大值

[英]Find for each sub array in multidimensional array, if element on fixed position is highest value for this sub array

Hello all.大家好。

For each sub array in $arr_rgb (Fig.01) I have to find: If element with $key number 1 is the highest number in this sub array, then return the $key number of the sub array (Fig.03 and Fig.04. So far, I can find highest number for each sub array – fig.02对于 $arr_rgb 中的每个子数组(图 01),我必须找到: 如果 $key 编号为 1 的元素是此子数组中的最高编号,则返回子数组的 $key 编号(图 03 和图 03)。 04. 到目前为止,我可以找到每个子数组的最大数字 - 图 02

In the attached image the "trouble" I have is explained.在附图中解释了我遇到的“麻烦”。

[1]:https://i.stack.imgur.com/1QMy3.png

And the code that I use so far:到目前为止我使用的代码:

<?php
$hex_splited = [
        ['00','00','00'], 
        ['10', '11', '10'], 
        ['F0', '1A', 'C3'],
        ['0F', 'FE', 'F4'],
       ];

$arr_rgb = [];
$count2 = count($hex_splited);

for ($i=0; $i < $count2; $i++) { 
    
    $inn_count = count($hex_splited[$i]);
    
    for ($j=0; $j < $inn_count; $j++) { 
            
        $val = hexdec($hex_splited[$i][$j]);
        $arr_rgb[$i][$j] = $val;

        foreach ($arr_rgb as $key => $value) {
            $resultMax[$key] = max($value);
        }
    }
}

echo "<pre>";
var_dump($resultMax);
echo "</pre>";

    echo "<table border='1'>";
for ($m=0; $m < $count2; $m++) {
    echo "<tr>";
    for ($k=0; $k < $inn_count; $k++) { 
        echo "<td>";
        echo $arr_rgb[$m][$k];
        echo "</td>";
    }
    echo "</tr>";
}
echo "</table>";

Determining the maximum using max only properly works for integers, so I would use array_map with hexdec to achieve that.使用max确定最大值仅适用于整数,因此我将使用array_maphexdec来实现。

Then all it needs is a comparison of the value at position 1 with that maximum, and if they are the same, then the index gets added to the result array:然后它所需要的只是将 position 1 处的值与该最大值进行比较,如果它们相同,则将索引添加到结果数组中:

$result = [];
foreach($hex_splited as $key => $value) {
  if(hexdec($value[1]) == max(array_map('hexdec', $value))) {
    $result[] = $key;
  }
}
var_dump($result);

This gets you 0, 1, 3 as result.结果是 0、1、3 0, 1, 3 (As IMHO it should be, according to your stated requirements - the value 00 at position 1 in the first sub-array is also the maximum of all values in that sub-array. If you need to exclude 0 values, then you'll have to modify accordingly.) (恕我直言,根据您声明的要求,第一个子数组position 1 处的值00也是该子数组中所有值的最大值。如果您需要排除 0 值,那么您将必须相应修改。)

EDIT:编辑:

if all elements are equal, then return nothing如果所有元素都相等,则不返回任何内容

Okay, that can also be implemented quite easily - we use array_count_values , and if the count of that is only 1, then that means all the elements had the exact same value.好的,这也可以很容易地实现 - 我们使用array_count_values ,如果它的计数只有1,那么这意味着所有元素都具有完全相同的值。

So then it becomes那么它变成了

foreach($hex_splited as $key => $value) {
  if(count(array_count_values($value)) != 1 &&
      hexdec($value[1]) == max(array_map('hexdec', $value))) {
    $result[] = $key;
  }
}

With that, you get [1, 3] as $result here.有了这个,你得到[1, 3]作为 $result 这里。

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