Selenium Python：弹出窗口上的“关闭”按钮 window 不可交互

Question

Can't seem to click on a 'close' button to close a pup up window that I have opened before to scrape the data that it displays. The button has the following html script:

<div class="closebutton" onclick="return hs.close(this)" title="Schließen"></div>

I was trying the following:

driver.find_element_by_xpath("//div[@class='closebutton']").click()

But I get the error:

Message: element not interactable

Anyone have a clue how to make the element interactable?

Answer 1

To click on the element you can use either of the following Locator Strategies :

• Using css_selector :

   driver.find_element_by_css_selector("button.closebutton[title='Schließen']").click()

• Using xpath :

   driver.find_element_by_xpath("//div[@class='closebutton' and @title='Schließen']").click()

---

Ideally, to click on the element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies :

• Using CSS_SELECTOR :

   WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button.closebutton[title='Schließen']"))).click()

• Using XPATH :

   WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[@class='closebutton' and @title='Schließen']"))).click()

• Note : You have to add the following imports:

   from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC