python 正则表达式：提取单引号或双引号之间的文本

Question

What I want to do is to extract all values between single or double quotation marks.

Let's say I have the following values.

"Alice's Adventures in Wonderland 1" 
"Alice's 'Adventures' in Wonderland 1" 
"Alice's "Adventures" in Wonderland 1" 
"Alice's Adventures \nin Wonderland 1" 
'Alice's Adventures in Wonderland 1'
'Alice's "Adventures" in Wonderland 1'
'Alice's 'Adventures' in Wonderland 1'
'Alice's Adventures \tin Wonderland 1'

And the desired outputs are:

Alice's Adventures in Wonderland 1
Alice's 'Adventures' in Wonderland 1
Alice's "Adventures" in Wonderland 1
Alice's Adventures \nin Wonderland 1
Alice's Adventures in Wonderland 1
Alice's "Adventures" in Wonderland 1
Alice's 'Adventures' in Wonderland 1
Alice's Adventures \tin Wonderland 1

How should I write the regex (using one regex expression for extracting all the desired values at once) to get the whole texts enclosed in the first and last quotation marks?

ps I want to use re.search(r"...", text) method

Answer 1

(?<?[\'\"])\n)? part to include \n s coming in between the actual text. \1 towards the end to match with quotation it started with ' or "

for match in re.finditer(r'^([\'\"])(.*?(?:(?<![\'\"])\n)?.*?)\1 *$', str1, re.M):
    print(match.group(2))

Alice's Adventures in Wonderland 1
Alice's 'Adventures' in Wonderland 1
Alice's "Adventures" in Wonderland 1
Alice's Adventures 
in Wonderland 1
Alice's Adventures in Wonderland 1
Alice's "Adventures" in Wonderland 1
Alice's 'Adventures' in Wonderland 1
Alice's Adventures  in Wonderland 1