关于 C 中 memory 分配的问题
[英]Question regarding memory allocation in C
问题描述
I am having a difficult time getting why the answer is 66 bytes to the following question:
我很难理解为什么以下问题的答案是 66 字节：
How much memory gets allocated for the data passed through the pointer in the main functions 2nd parameter(not considering the pointer size) in a 64 bit system, if the app is run with在 64 位系统中，如果应用程序运行在
./program alfa beta gamma
1 个解决方案
解决方案1
2 已采纳 2021-01-09 14:14:37
The best I could come up with is我能想到的最好的方法是
argv[0] ==> 8 bytes for pointer itself + 6 bytes for the data ( "./app" ) ==> 14 argv[0] ==> 8 个字节用于指针本身 + 6 个字节用于数据（ "./app" ）==> 14
argv[1] ==> 8 bytes for pointer itself + 5 bytes for the data ( "alfa" ) ==> 13 argv[1] ==> 8 个字节用于指针本身 + 5 个字节用于数据（ "alfa" ）==> 13
argv[2] ==> 8 bytes for pointer itself + 5 bytes for the data ( "beta" ) ==> 13 argv[2] ==> 8 个字节用于指针本身 + 5 个字节用于数据（ "beta" ）==> 13
argv[3] ==> 8 bytes for pointer itself + 6 bytes for the data ( "gamma" ) ==> 14 argv[3] ==> 8 个字节用于指针本身 + 6 个字节用于数据（ "gamma" ）==> 14
argv[4] ==> 8 bytes for the pointer ( NULL ) ==> 8 argv[4] ==> 8 个字节的指针（ NULL ）==> 8
TOTAL: 62总计：62
Maybe add 4 bytes for argc for 66 bytes??也许为argc添加 4 个字节以获得66个字节？
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