如何以小时、分钟和秒为单位将时间从一列提取到不同的单独列

Question

Crying time
20:31:47    
23:33:46
10:20:00
11:30:00
12:15:00
20:31:47
23:33:46
 10:20:00
 11:30:00
 12:15:00
 17:45:00
 19:20:00
 19:45:00
 22:30:00
  0:22:03
11:30:00
12:15:38
15:01:06
18:12:21 
20:56:39
23:30:00
11:40:00
13:30:00
18:29:42
21:15:41

How to extract the time from one column to different separate column in hours, minute, and second in Python?

Answer 1

Is that what you want?

Your "dat" file:

Crying time
20:31:47    
23:33:46
10:20:00
11:30:00
12:15:00

The code:

import re

with open("dat", "r") as msg:
    text = msg.readlines()

text = re.sub(r"[A-Za-z]","","".join(text)).replace(":"," ")

print (text)

Output:

20 31 47    
23 33 46
10 20 00
11 30 00
12 15 00

Your text data are in a "dat" file. You read the file line by line in a list using the readlines() method.

Then, you remove your header by using the re.sub method which replaces letters by nothing over the join product of your list (which yields a string). Finally, you replace the ":" by a space to print the output.

Alternatively, you can do:

with open("dat", "r") as msg:
    text = msg.readlines()

for i in range(1,len(text)):
    print (text[i].strip().replace(":"," "))

Which yields the same output.

Answer 2

I don't know what data you're using as its not formatted correctly, but if it was a string you can use.split to separate each hour minute and second into a list, which you can then call one each value

Crying_time = "20:31:47"
print(Crying_time.split(":"))

Would output

['20', '31', '47']

And can be seen by using

print(Crying_time[0])

Would output

'20'

If your numbers arent a string you can use str() to convert them to a string.

x = 1234
x = str(x)

Answer 3

As I understand. You have a file to read. Let's name it imsad.help . This file has this content:

Crying time
20:31:47    
23:33:46
10:20:00
11:30:00
12:15:00
20:31:47
23:33:46
 10:20:00
 11:30:00
...(continues)

Then, I understand you want to separate into 3 vectors:

• hours
• minutes
• seconds

So we can store these values in 3 different lists. The code may look something like:

hours = []
minutes = []
seconds = []

with open("imsad.help", "r") as fp:
    for line in fp: # Read the file, line by line
        t = line.strip() # strip removes whitespaces and new lines
        t = t.split(":") # split creates a list separating elements with ':'
                         # in between. In our case, it should create a list
                         # like: [hour, min, sec]

        if len(t) != 3:
            continue # This is the first row that contains ["Crying time"]
                     # So, we skip this and continue with other lines

        # cast to int and appends to each list
        hours.append(int(t[0]))
        minutes.append(int(t[1]))
        seconds.append(int(t[2]))

# Print only for demo
print("hours:", hours, "\n")
print("minutes:", minutes, "\n")
print("seconds:", seconds, "\n")

Begin learning Python:

• w3schools
• String methods (w3schools)

References:

• strip()
• split()
• open()