读取文件而不将其保存在本地 python/bottle

Question

Hi so basically I have a form that uploads a file

 <input class="btn btn-light" type="file" id="file" name="h" accept=".py">

I'm using bottle, so essentially I want to get the contents of the file but not have to save it locally. Using with open requires a path which I don't have as it is not saved locally.

f = request.POST['file']

I get the file using the above.

Is there any way I could upload the file without having to save it locally?

Any help would be much appreciated, I just need the name of the file and the contents.

Answer 1

No need to save the file (or to use BytesIO as suggested in a comment). You can simply read its contents:

from bottle import Bottle, request

app = Bottle()

@app.post("/upload")
def upload():
    f = request.POST["file_name"]
    text = f.file.read()
    return f"Read {len(text)} bytes from the uploaded file.\n"

app.run()

Output:

$ echo "This is the file to upload." > file.txt
$ curl http://127.0.0.1:8080/upload -F file_name=@file.txt
Read 28 bytes from the uploaded file.