使用 AJAX 将数据从 Javascript 发送到 PHP 以更新现有的 Z9EDB3C572B56B91542AF65948051 数据库

Question

I am working on the backend of my snake game project.I have been trying to update Max entry of mysql database by sending the new highscore to update.php webpage using xmlhttp request through post request of ajax.

In order to test whether my data is sent to update.php,I have also sent the test=all good to update.php.But when I am echoing,it is not displayed in the web browser thereby showing that no such data was successfully sent.

Please tell me why is it happening?

This is my code section of xml http request.

    '''
    highscore=score;
    document.querySelector("#my-high-score").textContent=highscore;
    var xhttp = new XMLHttpRequest();
    xhttp.open("POST", "update.php", true);
    xhttp.setRequestHeader("Content-type", "application/x-www-form- 
    urlencoded");
    xhttp.send(`highest_score=${highscore}&test="all good"`);
    '''

And this is the update.php file

    '''
    <?php
    session_start();
    $link=mysqli_connect("shareddb-x.hosting.stackcp.net","gameusers- 
    31353746432","havd5n897","gameusers- 
    3135374592");
    if(mysqli_connect_error())
    die ("connection is not successfull");
    echo "welcome user";
    $x=90;
    echo $x;
    echo $_POST['test'];
    if($_POST['highest_score'])
    {
    $high_score=$_POST['highest_score'];
    $email=$_SESSION['email'];
    if($_SESSION['highscore']<$high_score)
    {
    $query="UPDATE gameusers SET Max=$high_score WHERE Email= $email LIMIT 
    1";
    echo $high_score;
    mysqli_query($link,$query);
    echo "all fit";
    }
    }
    ?>
    '''

Please someone tell me where I am actually commiting the mistakes.

Answer 1

Try to remove to double quotes in "all good"

xhttp.send(`highest_score=${highscore}&test="all good"`);