在 Python 中将变量声明为十六进制

Question

I have a variable

s=64

This variable is in hex. But Python takes it as decimal. How do I declare it as a hex variable?

I know to declare something as hex, we use

s=0x64

But I have only

s=64

How can I go about this?

Answer 1

I think that is something missing in your code theory or question.

One thing is the value and one another is presentation (interpretation) . So the value is 100 (decimal), but it can be seen ( converted ) as a decimal or hexadecimal (or whatever you like):

>>> s=0x64
>>> s
100
>>> hex(s)
'0x64'
>>> h = int(str(0x64), 16)
>>> h
256

Python stores an integer as a decimal (by default). If you want to have a number that acts as a hexadecimal you should code your own class and use the conversion routines I showed above.

Answer 2

The number 64 in hex (base 16) is 100 . To achieve you answer, you should use a combination of hex() , int() and str() If you start with s = 64 and you want to end up with s = 100 which is the decimal value of 0x64 , consider this code:

s = 64
s = int(str(s), 16)

If you want something else, please clarify what, and note that you can try to achieve it yourself with some combination of hex(), int() and str()