[英]Right Click -Selenium - Python
I'm little bit struggling to find the correct way to perform a right click.我有点努力寻找执行右键单击的正确方法。
Here is a sample of my code:这是我的代码示例:
click_Menu = driver.find_element_by_id("Menu")
print(click_Menu.text)
action.move_to_element(click_Menu)
action.context_click(on_element=click_Menu)
action.perform()
All the imports are there.And print(click_Menu.text
) => returns "Menu", so the element has been found所有的导入都在那里。并且
print(click_Menu.text
) => 返回“Menu”,所以元素已经找到
Error:错误:
selenium.common.exceptions.StaleElementReferenceException: Message: stale element reference: element is not attached to the page document
I tried to add time.sleep()
but the result is the same.我试图添加
time.sleep()
但结果是一样的。
Any ideas please?请问有什么想法吗?
You simply need to pass only the element within context_click()
as follows:您只需要传递
context_click()
中的元素,如下所示:
context_click(click_Menu)
Your effective line of code will be:您的有效代码行将是:
action.context_click(click_Menu)
Optimizing your code block:优化你的代码块:
click_Menu = driver.find_element(By.ID, "Menu")
ActionChains(driver).move_to_element(click_Menu).context_click(click_Menu).perform()
This code will help you to solve the issue.此代码将帮助您解决问题。
from selenium.webdriver import ActionChains
Identifying the source element识别源元素
click_Menu= driver.find_element_by_xpath("your path")
or或者
click_Menu= driver.find_element_by_id("Menu")
Action chain object creation动作链 object 创建
action = ActionChains(driver)
Right-click operation and then perform右键操作然后执行
action.move_to_element(click_Menu).perform()
action.context_click(click_Menu).perform()
The easy way to overcome many of these types of errors is to just add some sort of delay:克服许多此类错误的简单方法是添加某种延迟:
import time
time.sleep(2)
Solution found.找到解决方案。
I was using an old ActionChains object.我使用的是旧的 ActionChains object。 So i reinstantiate it by creating a new one.
所以我通过创建一个新的来重新实例化它。
action1 = ActionChains(driver)
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