在 Android Studio 中构建 AAR

Question

It's my first time building AAR

The official site says that All I hate to do is build APK and AAR will be assembled

Here's the quote:

But when I choose "Build Apk(s)" nothing happens.

Another tutorial says I have to choose Gradle-> library name -> tasks-> build-> :assembleRelease .

But there is no such thing:

How can I assemble library as AAR?

here's my gradle:

plugins {
    id 'com.android.library'
    id 'kotlin-android'
    id 'kotlin-kapt'
}

android {
    compileSdkVersion 29
    buildToolsVersion "29.0.3"

    defaultConfig {
        minSdkVersion 17
        targetSdkVersion 29
        versionCode 1
        versionName "1.0"

        testInstrumentationRunner "androidx.test.runner.AndroidJUnitRunner"
    }

    buildTypes {
        release {
            minifyEnabled false
            proguardFiles getDefaultProguardFile('proguard-android-optimize.txt'), 'proguard-rules.pro'
        }
    }
    compileOptions {
        sourceCompatibility JavaVersion.VERSION_1_8
        targetCompatibility JavaVersion.VERSION_1_8
    }
    kotlinOptions {
        jvmTarget = '1.8'
    }
}

dependencies {

    implementation "org.jetbrains.kotlin:kotlin-stdlib:$kotlin_version"
    implementation 'androidx.core:core-ktx:1.3.2'
    implementation 'androidx.appcompat:appcompat:1.2.0'
    implementation 'com.google.android.material:material:1.2.1'
    testImplementation 'junit:junit:4.+'
    androidTestImplementation 'androidx.test.ext:junit:1.1.2'
    androidTestImplementation 'androidx.test.espresso:espresso-core:3.3.0'
    def room_version = "2.2.3"
    implementation "androidx.room:room-runtime:$room_version"
    kapt "androidx.room:room-compiler:$room_version"
    implementation "androidx.room:room-ktx:$room_version"
    implementation "androidx.room:room-rxjava2:$room_version"
    implementation 'com.google.code.gson:gson:2.8.2'
}

Answer 1

Just click assemble or add buildTypes.debug . While you don't have buildTypes.debug defined, it won't generate the tasks you are looking for (as there only is one configuration present there and so there is nothing to tell apart).