iterrows() 循环只读取最后一个值，只修改第一行

Question

I have a dataframe test . My goal is to search in the column t1 for specific strings, and if it matches exactly a specific string, put that string in the next column over called t1_selected . Only thing is, I can't get iterrows() to go over the entire dataframe, and to report results in respective rows.

for index, row in test.iterrows():
    if any(['ABCD_T1w_MPR_vNav_passive' in row['t1']]):
        #x = ast.literal_eval(row['t1'])
        test.loc[i, 't1_selected'] = str(['ABCD_T1w_MPR_vNav_passive'])

I am only trying to get ABCD_T1w_MPR_vNav_passive to be in the 4th row under the t1_selected , while all the other rows will have not found . The first entry in t1_selected is from the last row under t1 which I didn't include in the screenshot because the dataframe has over 200 rows.

I tried to initialize an empty list to append output of

import ast
x = ast.literal_eval(row['t1'])

to see if I can put x in there, but the same issue occurred.

Is there anything I am missing?

Answer 1

for index, row in test.iterrows():
    if any(['ABCD_T1w_MPR_vNav_passive' in row['t1']]):
        #x = ast.literal_eval(row['t1'])
        test.loc[index, 't1_selected'] = str(['ABCD_T1w_MPR_vNav_passive'])

Where index is the row its written to. With i it was not changing