获取列表项及其名称的所有组合

Question

I want to get all the combinations of a list of values. I was able to do that via this code:

list_of_all_features_to_combine = [name1, name2, name3]
    
    
import itertools
all_combinations = []
for L in range(0, len(list_of_all_features_to_combine)+1):
    for subset in itertools.combinations(list_of_all_features_to_combine, L):        
         all_combinations.append(subset)

I print one combination as follows:

print(all_combinations[0])

Of course, I only get the values.

My problem is that I want to know "which" items are combined, so I need the variable names. The only way to do that, that I can imagine, is to have a list of dictionaries with the names as string and then combine these, but I'm sure, that there is a simpler and more elegant way of doing that. Maybe some method of how to retrieve the variable names, such that I get an output like name1, name2: (1,2)

Answer 1

Perhaps this is what you're looking for:

from itertools import combinations

name1, name2, name3 = 10,20,30
names = ["name1", "name2", "name3"]
list_of_all_features_to_combine = [name1, name2, name3]

my_globals = globals()
name_combs = [subset for L in range(len(names)+1) 
              for subset in combinations(names,L)]
result = {t:tuple(my_globals[var] for var in t) for t in name_combs }

The result looks like this:

print (result)

{(): (),
 ('name1',): (10,),
 ('name2',): (20,),
 ('name3',): (30,),
 ('name1', 'name2'): (10, 20),
 ('name1', 'name3'): (10, 30),
 ('name2', 'name3'): (20, 30),
 ('name1', 'name2', 'name3'): (10, 20, 30)}

To access only the combinations of values:

print (list(result.values()))

[(), (10,), (20,), (30,), (10, 20), (10, 30), (20, 30), (10, 20, 30)]

To access only the combinations of names:

print (list(result.keys()))
[(), ('name1',), ('name2',), ('name3',), ('name1', 'name2'), ('name1', 'name3'), ('name2', 'name3'), ('name1', 'name2', 'name3')]

Answer 2

I am not sure if I got you correctly, but is this what you looking for? Or maybe part of it?

l = ["name1", "name2", "name3"] 
x = [x for x in itertools.permutations(l, r=3)]
for i in enumerate(x):
    print(i)

If you can explain maybe more specific?