Integer：为什么它在 Linux 上工作而不在 Windows 上工作

Question

I have a big Problem. I am a beginner in C, my task is to program a "robot" which is circling my room (theoretically). I tried it with this method: index = 0; if you type in "yes" it will add 1 on the index, if you answer with "no" or something else it just print something. If index >= 4 it will print something and stop the program.

I compiled it on my Raspberry PI 4 with cc and it works totaly fine but if i use Code Blocks (i think it uses GCC) it will set the Integer to 115 (if i type in yes, otherwise it will be 0) and add 1 more to 116, i absolutly dont know why. But i think its a Problem with the compiler. How can solve this?

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void main()
{
char wall[2];
int index;
index = 0;
 while(wall[0] == '\0'){ // Check if wall[0] is empty

        printf("Go!\n");
        printf("Is the Wall already there?\n");
        printf("Number: %i\n", index);
        scanf("%s", wall);

      if(strcmp(wall, "yes") == 0){
          printf("Turn!\n");
          index++;
          if(index >= 4){
              printf("You have circled the room once %i!\n", index);
              exit(0);
          }
      }
      else if(strcmp(wall, "no")  == 0){
          printf("Sad... go on\n");
      }
      else {
            index++;
          printf("You can answer only with yes or no!\n");
      }
      wall[0] = '\0';
}
}

Answer 1

my mistake was to use char wall[2] its to small for words like yes, i just changed it to

char wall[20]

Answer 2

How much space is there in char wall[2] , and how much space do you think you need for the string yes , including the zero byte to mark the string's end?