返回对象数组中的最大数

Question

im trying to figure out how i can return the most expensive price in this array of items.

let items = [
    {
      itemName: "Effective Programming Habits",
      type: "book",
      price: 13.99
    },
    {
      itemName: "Creation 3005",
      type: "computer",
      price: 299.99
    },
    {
      itemName: "Finding Your Center",
      type: "book",
      price: 15.00
    }
  ]

I know the.reduce() method is specific for arrays. But im not sure what else i could use to determine what the most expensive price is.

I have also tried using Math.max() but im not quite sure how i would use it in this case

Answer 1

You can use

Math.max(...items.map(item => item.price));

to get the highest price.

Answer 2

Using .reduce :

 const items = [ { itemName: "Effective Programming Habits", type: "book", price: 13.99 }, { itemName: "Creation 3005", type: "computer", price: 299.99 }, { itemName: "Finding Your Center", type: "book", price: 15.00 } ]; const mostExpensiveItem = items.reduce((acc,item) => { const maxPrice = acc.price || Number.MIN_VALUE; if(item.price > maxPrice) acc = item; return acc; }, {}); console.log(mostExpensiveItem); console.log(mostExpensiveItem.price);

Using for-loop :

 const items = [ { itemName: "Effective Programming Habits", type: "book", price: 13.99 }, { itemName: "Creation 3005", type: "computer", price: 299.99 }, { itemName: "Finding Your Center", type: "book", price: 15.00 } ]; let mostExpensiveItem = {}; for(let i = 0; i < items.length; i++) { const item = items[i]; const maxPrice = mostExpensiveItem.price || Number.MIN_VALUE; if(item.price > maxPrice) mostExpensiveItem = item; } console.log(mostExpensiveItem); console.log(mostExpensiveItem.price);

Note: If you're only looking for the price , then, you can keep track of this property as a number instead of the whole object.

Answer 3

Use map and Math.max

 let items = [ { itemName: "Effective Programming Habits", type: "book", price: 13.99 }, { itemName: "Creation 3005", type: "computer", price: 299.99 }, { itemName: "Finding Your Center", type: "book", price: 15.00 } ] const exp = Math.max(...items.map(({ price }) => price)); console.log(exp)

Answer 4

Try below snippet

let index,highest = 0;

for ( let item in items ) {
    if(items[item].price > highest ) {
    index  = item;
    highest = items[item].price;
 }
} 
// highest price item
console.log(items[index].price)