如何使用枚举 function 和 for 循环从字符串中删除不需要的空格

Question

i have this code but it is not working.. i don't know what's wrong in this code

djtext = "g o d  i s   gre at"
analyzed = ""
for index, char in enumerate(djtext):
    if not(djtext[index] == " " and djtext[index+1]==" "):
      analyzed = analyzed + char
print(analyzed)

I want the output like this

god is great

But it gave me this output

godis gre at

Answer 1

You can achieve the result you want by using split to split the string on two spaces and then join the parts again with the spaces removed

' '.join(word.replace(' ', '') for word in djtext.split('  ') if word)

Answer 2

Consider this alternative solution using regular expressions:

import re
djtext = "g o d  i s   gre at"
analyzed = re.sub(r' (.)', lambda x: x.group(1), djtext)
print(analyzed)

This matches a space followed by any character , and replaces all such sequences with just the character that was matched.

This gives the desired output:

god is great

If you want to stick with your original approach, then you need to add an extra condition to make it work. Your original code covers one cases ( reducing multiple spaces) but misses the other cases ( removing the unnecessary spaces).

The following version is the correct version of your code. It adds the condition char == " " and djtext[index - 1] != " " , which just checks that if the current character is a space, the character before it is not also a space. In such a case, you wouldn't want to keep the space.

djtext = "g o d  i s   gre at"
analyzed = ""
for index, char in enumerate(djtext):
    if not((char == " " and djtext[index + 1] == " ") or (char == " " and djtext[index - 1] != " ")):
        analyzed += char
print(analyzed)

Side note: for readability, I've switched djtext[index] to char and analyzed = analyzed + char to analyzed += char .