如何打印两次相同的随机数？

Question

I try to make a code that prints two equal random values in a text.

import random
archivo=open('Ejercicio3.txt', 'w')
up=0
insert=int(input('Valor: '))
for i in range(insert):
    up+=1
    n1=random.randint(10, 100)
    n2=random.randint(10, 100)
    archivo.write(f'{up}.-    {n1} - {n2} = {n1-n2}\n\n')

    print(f'{up}.-    {n1} - {n2} = {n1-n2}')
    archivo.write(f'{n1-n2}\n')#This is the problem, because the code write numbers different random

archivo.close()

What I want is for it to do something similar to this:

import random
archivo=open('Ejercicio1.1.txt', 'w')
up=0
insert=int(input('Valor: '))
for i in range(insert):
    up+=1
    n1=random.randint(10, 100)
    n2=random.randint(10, 100)

    archivo.write(f'{n1} - {n2} =''\n\n')

up=0
archivo.write('---------------------------------------------\n')
for i in range(insert):
    up+=1
    n1=random.randint(10, 100)
    n2=random.randint(10, 100)
    archivo.write(f'{n1-n2}''\n\n')#Except this part, I want it to be exactly the same as the result of the subtraction above. 
archivo.close()

The result i want, is this: Example

Someone can I help me? Thanks very much. Regards

Answer 1

you can use random.seed() and set the same seed two times.

import random

random.seed(0)
print(random.random())
#prints a random number    

random.seed(0)
print(random.random())
#prints the same random number

Answer 2

Just store the results in a list and then iterate over it again.

import random
archivo=open('Ejercicio1.1.txt', 'w')
up=0
results = []
insert=int(input('Valor: '))
for i in range(insert):
    up+=1
    n1=random.randint(10, 100)
    n2=random.randint(10, 100)
    results.append(n1-n2)
    archivo.write(f'{n1} - {n2} = {n1 - n2} ''\n\n')

up=0
archivo.write('---------------------------------------------\n')
for i in range(insert):
    up+=1
    archivo.write(f'{results[i]}''\n\n')
archivo.close()