[英]How do I incorporate one function into another?
I have to define two separate functions z(x, mu, c)
and landau(x, A, mu, c)
.我必须定义两个单独的函数
z(x, mu, c)
和landau(x, A, mu, c)
。 z = (x-mu)/c
and landau = 1.64872*A*np.exp(-0.5(z+np.exp(-z)))
z = (x-mu)/c
和landau = 1.64872*A*np.exp(-0.5(z+np.exp(-z)))
As they share variables I have tried to define z
inside the definition of landau
as a function itself and not as a function.由于它们共享变量,我试图在landau的定义中将
z
定义为landau
本身,而不是function。 Also, I have tried to define z
as a function outside the definition of landau
.另外,我试图将
z
定义为 function 定义之外的landau
。 However, nothing I try seems to work.但是,我尝试的任何方法似乎都不起作用。 Either python tells me
"'float' object is not callable"
or "bad operant type for unary -: 'function'"
. python 告诉我
"'float' object is not callable"
或"bad operant type for unary -: 'function'"
。 Is there a quick fix for this?有没有快速解决这个问题的方法?
landau(1,1,1,1)
should give an answer that's roughly equal to 1 landau(1,1,1,1)
应该给出一个大致等于 1 的答案
def landau(x, A, mu, c): # Functie Landau met variabelen x, A, c en mu
# A = amplitude
# c = schaalparameter
# mu = positieparameter
def z(x, mu, c):
return (x-mu)/c
return 1.64872*A*np.exp(-0.5(z(x, mu, c)+np.exp(-z(x, mu, c))))
You missed a * in -0.5 * (z(x
. At least I'm assuming it's supposed to be a multiplication.您错过了
-0.5 * (z(x
) 中的 * 。至少我假设它应该是乘法。
import numpy as np
def landau(x, A, mu, c): # Functie Landau met variabelen x, A, c en mu
# A = amplitude
# c = schaalparameter
# mu = positieparameter
return 1.64872 * A * np.exp(-0.5 * (z(x, mu, c) + np.exp(-z(x, mu, c))))
def z(x, mu, c):
return (x - mu) / c
landau(1, 1, 1, 1)
0.9999992292814129
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