如何在两个 arguments function 中仅打印第一个参数？

Question

I have a txt.file and string input as an arguments, given string input my function will print corresponding line/string from the file in a set. And file has one word per line.

def angram(s1,s2):
    st = set()
    if sorted(s1) == sorted(s2):
       st.add(s1)
  return st
angram('my.txt', 'top')

expected output: {'pot'}

but output I get {'pot','top'}

I do not want the string input in set. I want only output result from file. Any way to do that??

Answer 1

You need to use Python builtin functions for reading files. https://www.geeksforgeeks.org/read-a-file-line-by-line-in-python/

Given:

car
pto
pot

Output:

{'pot', 'pto'}

Code:

def anagram(s1,s2):
    st = set()
    fh = open('my.txt')
    target = sorted(s2)
    while True:
        line = fh.readline()      # while there is line to read in the file
        check = line.strip('\n')  # some lines will include "\n" in index 0 - remove it
        if sorted(check) == target:
          st.add(check)
        if not line:
            break
    fh.close()
    st.remove(s2) # the user doesn't want the same word as the target (s2) to be included
    return st
anagram('my.txt', 'top')