如何将通过外键连接的两个表中的所有行迭代到 PHP、CodeIgniter、MySQL 中的单个表中

Question

Say I have Table A and Table B in my SQL database.

TABLE A (Users)

userID	Name	Contact
userA	John	2292
userB	Dave	3383

TABLE B (Sports)

sportID	Name	trainer_userID
sportA	Basketball	userB
sportB	Baseball	userA
sportC	Soccer	userC

On my PHP page, I want to combine the two tables, such that the foreign key trainer_userID connects to their respective users. I can already iterate through each users and show Table A, but can't think of ways to combine both tables such that the output would be:

userID	Name	Contact	Sport Handled ID	Sport Handled
userA	John	2292	sportB	Baseball
userB	Dave	3383	sportA	BasketBall

Answer 1

Look up JOINS in SQL. This is exactly what relational databases are for. Don't implement sql in loop, databases do it better. Welcome to SO. – danblack 35 mins ago

Solved my problem using the JOINS technique and by using databases instead of looping.

SELECT * FROM tableA
INNER JOIN tableB
   ON tableA.userID = tableB.trainer_userID;