使用python3.6中的多个键在dict内分组列表

Question

Here I'm given input JSON data.在这里，我得到了输入 JSON 数据。 Anyone help me to solve expected result below format.任何人都可以帮助我解决以下格式的预期结果。 I'm trying to solve but I can't get expected result format.我正在尝试解决，但我无法获得预期的结果格式。

sub_type_list = [
   {
    'name':'blood',
    'transaction_points':[
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':''
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id': "423"
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':'1'
        }
    ]
  },
  {
    'name':'blood',
    'transaction_points':[
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':'123'
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id':''
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':''
        }       
    ]           
  },
  {
    'name':'body',
    'transaction_points':[
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':''
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id':'42'
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':'11'
        }
    ]
  },
  {
    'name':'blood',
    'transaction_points':[
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':'87'
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id':'50'
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':'25'
        }
    ]
  }
 ]

Expected Result below预期结果如下

 [{
'name': 'blood',
'transaction_points':[
  [
      { 'point': '(1-10)', 'value': '', 'symbol': '', 'service_id': ''},
      {'point': '(1-10)', 'value': '', 'symbol': '', 'service_id': '123'},
      { 'point': '(1-10)', 'value': '', 'symbol': '', 'service_id': '87'}       
],
[     
     {'point': '(10-20)', 'value': '', 'symbol': '', 'service_id': '423'},
     {'point': '(10-20)', 'value': '', 'symbol': '', 'service_id': ''},
     {'point': '(10-20)', 'value': '', 'symbol': '', 'service_id': '50'}    
],
 [
     {'point': '(20-30)', 'value': '', 'symbol': '', 'service_id': '1'},
     '{point': '(20-30)', 'value': '', 'symbol': '', 'service_id': ''},
     '{point': '(20-30)', 'value': '', 'symbol': '', 'service_id': '25'}
    
 ]
]
},{
'name': 'body',
'transaction_points':[
  [
     {'point': '(1-10)', 'value': '', 'symbol': '', 'service_id': ''}
    
],
[ 
    {'point': '(10-20)', 'value': '', 'symbol': '', 'service_id': '42'} 
],
 [
    {'point': '(20-30)', 'value': '', 'symbol': '', 'service_id': '11'}     
]
]
}
]

Here I'm using given below code and try to generate expected result在这里，我使用下面给出的代码并尝试生成预期的结果

 result = dict()
 final_result = []
 for id, i in enumerate(sub_type_list):
     if result.get(i["name"]):
          result[i["name"]].extend(i["transaction_points"])
     else:
          result[i["name"]] = i["transaction_points"]
 for i in result.keys():
      final_result.append({"name": i, "transaction_points": result[i]})

final_result list produce give below result but I want expected result above final_result 列表产生下面的结果，但我想要上面的预期结果

 [
 {
    'name':'blood',
    'transaction_points':[
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':''
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id':'423'
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':'1'
        },
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':'123'
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id':''
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':''
        },
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':'87'
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id':'50'
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':'25'
        }
    ]
},
{
    'name':'body',
    'transaction_points':[
        {
            'point':'(1-10)',
            'value':'',
            'symbol':'',
            'service_id':''
        },
        {
            'point':'(10-20)',
            'value':'',
            'symbol':'',
            'service_id':'42'
        },
        {
            'point':'(20-30)',
            'value':'',
            'symbol':'',
            'service_id':'11'
        }
      ]
    }
   ]

Answer 1

You need to have a look at groupby() function of itertools library.您需要查看 itertools 库的groupby() function。

使用python3.6中的多个键在dict内分组列表

问题描述

1 个解决方案

解决方案1
0 2021-01-19 10:59:18

使用python3.6中的多个键在dict内分组列表

问题描述

1 个解决方案

解决方案1 0 2021-01-19 10:59:18

解决方案1
0 2021-01-19 10:59:18