（Python）如何制作 function 来计算随机列表中特定数字的数量？

Question

My program is to create a randomized list of 1-10 for a range of 1000, each number has to be randomized through 1-10 then once that is done. I need to identify how many 1s, 2s,3s, and 4,s, etc there are in the 1000 randomized numbers.

import random
#Printing a random list of 1 through 10
#loop to loop 1000 times
for i in range(1000):
  #lisitng random numbers 1 through 10 inclusive 
  l1 = random.randint(1, 10)
  l2 = random.randint(1, 10)
  l3 = random.randint(1, 10)
  l4 = random.randint(1, 10)
  l5 = random.randint(1, 10)
  l6 = random.randint(1, 10)
  l7 = random.randint(1, 10)
  l8 = random.randint(1, 10)
  l9 = random.randint(1, 10)
  l10 = random.randint(1, 10)
  #printing the numbers in a list form 
  print(l1,l2,l3,l4,l5,l6,l7,l8,l9,l10)
  #A  function to identify how many X are there in each number 
   

If you need more information on this please tell me in the comments.

Answer 1

First you need to generate the list, simplest way to do this is like so:

randomList = [random.randint(1, 10) for x in range(1, 1000)]

Next you need to count how many of each number there are in that array, you can do that like this:

randomCounts = [ (x, randomList.count(x)) for x in range(1, 10)]

This will output an array of tupples, where the first value of the tuple represents a number, and the second represents how often that number occurs in the randomList.

You could then do something like this to find how often the number N occured in that list:

amount = randomCounts[n - 1][1]

Answer 2

This should do the trick:

import random

random_list = []

for i in range(1000):
    random_list.append(random.randint(1, 10))

for i in range(10):
    print("{} was in the list exactly {} times.".format(i+1, random_list.count(i+1)))

Answer 3

Use collections.Counter to tally the occurrences of each number, and use random.choices to create your random numbers within a range:

from collections import Counter
from random import choices

counter = Counter(choices(range(1, 10 + 1), k=1000))

for key, value in sorted(counter.items()):
    print(f"Number of {key}s: {value}")

Output:

Number of 1s: 87
Number of 2s: 102
Number of 3s: 93
Number of 4s: 116
Number of 5s: 109
Number of 6s: 79
Number of 7s: 105
Number of 8s: 105
Number of 9s: 104
Number of 10s: 100
>>> 

Answer 4

It seems you want to:

1. create a list of 1000 items where each item can be a random integer in the range from 1 to 10.
2. count how many of each integer there are in that list.

So, let's create a list of 1000 items where each item can be a random integer in the range from 1 to 10:

import random
my_list = [random.randint(1, 10) for x in range(0, 1000)]

Then, let's count how many 1s, 2s, 3s, ..., 10s there are in my_list :

count = [my_list.count(i+1) for i in range(0, 10)]

Now count is a list like:

Number of 1s	Number of 2s	...	Number of 10s
32	21	...	43

If you want to print (python 3.x):

for idx, number in enumerate(count):
    print(f'There are {number} item of {idx+1}s')