计算一个数字中一行中最多的零个数| Python

Question

I want to create a function that asks for a number and then sees the most amount of zeros in a row and returns its value (ex: 5400687000360045 -> 3 | 03500400004605605600 -> 4). So far this is all I got but it isn't working:

def zeros():
    num = input('Write a number: ')
    row = 0
    result = 0
    for i in num:
        if i == '0':
            while i == '0':
                row += 1
                if row > result:
                    result = row
    return result

What's wrong?

EDIT: This is what the desired output should be:

zeros()
Write a number: 03500400004605605600
4

My current output is nothing, meaning it's not returning anything

Answer 1

This should do it.

def zeros():
    num = input('Write a number: ')
    row = 0
    count = 0
    for i in num:
        if i == '0':
            count += 1
        else:
            row = max(row, count)
            count = 0
    row = max(row, count)
    return row

Your code is getting stuck in an infinite loop in inner while

Answer 2

To do it your way, you just need to keep track of whether the number is a 0 or not (ie to know if it is a row of zeros or if you need to restart the count). Something like this would work:

def zeros():    
    num = input('Write a number: ')
    row = 0
    result = 0
    for i in num:
        if i != '0':
            row = 0
        else:
            row += 1
            if row > result:
                result = row
    return result

Output is as you would expect.

If you know regex, you could achieve this with much less code using:

import re

def zeros():    
    num = input('Write a number: ')
    result = max(map(len, re.findall(r'0+', num)))
    return result

Answer 3

Is this helpful to you..? regex (Regular expression operations) is a very handy tool which could make your life easier. Please have look at Regular expression operations

import re
def zeros():
    num = input('Write a number: ') 
    return max(re.findall("(0+0)*", (num)))

output: 000

---

def zeros():
    num = input('Write a number: ') 
    return len(max(re.findall("(0+0)*", (num))))

output: 3

Answer 4

I think this might work

num = input()

countOfZeros = 0
for i in range(len(num)-1):
    curr = 0
    if num[i] == num[i+1]:
       curr = 0
       if curr > countOfZeros:
           countOfZeros = curr
       else:

           countOfZeros += 1
print(countOfZeros - 1 )