将 curl 请求转换为 python

Question

Im trying to turn this curl request into a python code. I want to eventually be able to save this to a csv but I need to get connected first.

curl --compressed -H 'Accept: application/json' -H 'X-Api-Key: 123abc' 'https://us.market-api.kaiko.io/v2/data/trades.v1/exchanges/cbse/spot/btc-usd/aggregations/count_ohlcv_vwap?interval=1h'

I started with this:

import requests
import json

key='api-key'

url = 'https://us.market-api.kaiko.io/v2/data/trades.v1/exchanges/'
s = requests.Session()
s.auth = (key)

headers = {
   *not sure how to do this*
}
r = requests.get(url, headers=headers)

the docs say this needs to be in the header:

Accept: application/json Accept-Encoding: gzip:

How do I include the api key? how do I save the data once its returned?

Answer 1

X-Api-Key would be a request header, so you can include it in your headers variable, like this:

headers = {
   "X-Api-Key": key,
   "Accept": "application/json",
   "Accept-Encoding": "gzip"
}

(took the others ones from your current curl request)

You can get the data by using r.text , like this:

print(r.text)

Your code should look like this:

import requests
import json

key='api-key'

url = 'https://us.market-api.kaiko.io/v2/data/trades.v1/exchanges/'

headers = {
   "X-Api-Key": key,
   "Accept": "application/json",
   "Accept-Encoding": "gzip"
}

r = requests.get(url, headers=headers)
print(r.text)

If you want to get a json object instead, you can use r.json()