正则表达式匹配字符串中的单词或单词之间的点（可选）

Question

I'm currently working on an issue that matches a word between special characters. Optionally matches words in between dot.

I currently tried below regex pattern it works fairly well in words that have dot in between but I struggled to make it work with word without dot.

[^\W\s]+\.+[^\s\W)]+

Given the string:

  ,DECODE(T3.ATEST,' ',T3.BATEST
                           ,DECODE(NVL(T4.BATEST,'9') 
                                 ,'1',NVL(T4.BATEST,' ')
                                     ,T3.BATEST))      

it matches the following:

T3.ATEST
T3.BATEST
T4.BATEST
T4.BATEST
T3.BATEST

Now trying this regex pattern above without dot in between:

  ,DECODE(ATEST,' ',BATEST
                           ,DECODE(NVL(BATEST,'9') 
                                 ,'1',NVL(BATEST,' ')
                                     ,BATEST))      

I need a regex that also has the output below:

ATEST
BATEST
BATEST
BATEST
BATEST

Is it possible to optionally match a words between dot?

Thank you for the help.

Answer 1

You can use

/(?:\w+\()+|\b(\w+(?:\.\w+)?)\b(?!')/g

If your JavaScript environment supports ECMAScript 2018+, you may use

/(?:\w+\()+|(?<!')\b(\w+(?:\.\w+)?)\b(?!')/g

See the regex demo #1 and regex demo #2 . Details :

• (?:\w+\()+ - match one or more sequences of one or more word chars and then ( char
• | - or
• \b - match a word boundary
• (?<!') - ' is not allowed to be immediately to the left of the current location
• (\w+(?:\.\w+)?) - Group 1: one or more word chars and then an optional occurrence of a . and then one or more word chars
• \b - a word boundary
• (?!') - not followed with ' char.

See the JavaScript demo:

 const text = ",DECODE(T3.ATEST,' ',T3.BATEST\n,DECODE(NVL(T4.BATEST,'9')\n,'1',NVL(T4.BATEST,' '),T3.BATEST)),DECODE(ATEST,' ',BATEST,DECODE(NVL(BATEST,'9'),'1',NVL(BATEST,' '),BATEST))"; const regex = /(?:\w+\()+|\b(\w+(?:\.\w+)?)\b(?;')/g, let results=[];m. while(m = regex.exec(text)) { if (m[1];== undefined) { results.push(m[1]); } } console.log(results);

If your JavaScript environment supports matchAll :

 const text = ",DECODE(T3.ATEST,' ',T3.BATEST\n,DECODE(NVL(T4.BATEST,'9')\n,'1',NVL(T4.BATEST,' '),T3.BATEST)),DECODE(ATEST,' ',BATEST,DECODE(NVL(BATEST,'9'),'1',NVL(BATEST,' '),BATEST))"; const regex = /(?:\w+\()+|\b(\w+(?:\.\w+)?)\b(?;')/g. const results = Array.from(text,matchAll(regex). x => x[1]);filter(x =>.;x); console.log(results);