[英]How to get result from a column with combined data?
data: 数据:
id bb
1 14,35
2 5,11,12,125,36
3 3,23,45,15,1
4 651
5 5,1,6
6 1,7
For example, i wan't get id which with value '1'. 例如,我将无法获得ID,其值为'1'。 So id(3,5,6) should return , but not others with '14' or '11'.
因此id(3,5,6)应该返回,但其他不返回'14'或'11'的返回值。
DB: Mysql DB:MySQL
This is not the most efficient solution but it might give you what you want off the table: 这不是最有效的解决方案,但可能会给您带来您想要的东西:
select id from MyTable where bb like '%,1,%' union
select id from MyTable where bb like '1,%' union
select id from MyTable where bb like '%,1' union
select id from MyTable where bb like '1'
cheers 干杯
select * from test where find_in_set('1',bbb)
要么
select * from test where bbb REGEXP '(^|,)1(,|$)'
Am I missing something? 我想念什么吗?
SELECT *
FROM MyTable
WHERE (id = 3) or (id = 5) or (id = 6)
您可以从mytable中选择* *,例如ID为“ 14%”或“ 11%”
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