我可以使用 printf 打印 c++ 字符串数组的元素吗

Question

#include <iostream>
using namespace std;

int main()
{
    string s[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    int a, b;
    cin >> a >> b;
    for (int i = a; i <= b; i++)
        (i >= 1 && i <= 9) ? printf("%d\n", s[i - 1]) : i % 2 ? printf("odd\n") : printf("even\n");
    return 0;
}

I am using a ternary operator to print integer into word if it lies between 1 to 9 otherwise printing whether it's even or odd. I am not able to use cout in ternary operator and if I used printf then it's printing a character. can anybody tell me how to do that. I wanted to do the entire stuff in one line, is it possible?

Answer 1

You can use cout . Like so:

#include <iostream>


int main()
{
    std::string s[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    int a, b;
    std::cin >> a >> b;
    for (int i = a; i <= b; i++)
        std::cout << ((i >= 1 && i <= 9) ? s[i-1]: (i % 2) ? "odd": "even") << "\n";
    return 0;
}

Answer 2

%d prints decimal numers to the console. To print strings, you need the %s token and make sure that you get the const char* of it using s[i - 1].c_str() .