从给定的单词列表中生成具有“N”长度的所有可能组合（寻找不重复）

Question

I would like to generate words sentence with given length. Here i would like to get output without any repeat of characters or words.

With current code i am receiving outputs

example example example example example
example example example example example2
example example example example example3
example example example example example4
example example example example example5
example example example example example6
example example example example example7
example example example example example8
example example example example example9
example example example example2 example
example example example example2 example2

But i would like to receive output with random words as without any word repeated in sentence

example example1 example2 example3 example4
example1 example2 example3 example4 example5
example5 example1 example2 example3 example4
example6 example4 example2 example5 example1

Here is the code

import numpy as np 
# Python 3 program to print all 
# possible strings of length k 
    
# The method that prints all 
# possible strings of length k. 
# It is mainly a wrapper over 
# recursive function printAllKLengthRec() 
def printAllKLength(set, k): 

    n = len(set) 
    printAllKLengthRec(set, "", n, k) 

# The main recursive method 
# to print all possible 
# strings of length k 
def printAllKLengthRec(set, prefix, n, k): 
    
    # Base case: k is 0, 
    # print prefix 
    if (k == 0) : 
        print(prefix) 
        return

    # One by one add all characters 
    # from set and recursively 
    # call for k equals to k-1 
    for i in range(n): 

        # Next character of input added 
        newPrefix = prefix + set[i] 
        
        # k is decreased, because 
        # we have added a new character 
        printAllKLengthRec(set, newPrefix, n, k - 1) 

# Driver Code 
if __name__ == "__main__": 
    
    
    print("\nSecond Test") 
    set2 = ['example ', 'example2 ', 'example3 ', 'example4 ', 'example5 ', 'example6 ', 'example7 ', 'example8 ', 'example9 '] 
    k = 5
    printAllKLength(set2, k) 

# This code is contributed 
# by ChitraNayal 

Answer 1

You just have to keep track of the characters you haven't used in your set, so you don't repeat them. Here I have a list comprehension called remaining_char:

def printAllKLength(set, k):
    n = len(set)
    printAllKLengthRec(set, "", n, k)

def printAllKLengthRec(set, prefix, n, k):
    if (k == 0):
        print(prefix)
        return
    remaining_char = [char for char in set if char not in prefix]
    for i in range(len(remaining_char)):
        newPrefix = prefix + remaining_char[i]
        printAllKLengthRec(set, newPrefix, n, k - 1)

Answer 2

In response to your comment, to add space between the words, you can modify your wrapper function as follows:

def printAllKLength(set, k):
    set = {word + "   " for word in set}
    n = len(set)
    printAllKLengthRec(set, "", n, k)