在 python 中对列表进行切片时迭代地跳过 n 个元素

Question

I have a big array of 10573 elements and I want to group them into chunks but skipping two elements after each chunk.

I have the code to divide the list into chunks:

chunk_size= 109
for i in range(0, len(ints), chunk_size):
    chunk = ints[i:i+chunk_size]

But how do I skip or delete two elements from the big list iteratively, ie, after attaining each chunk of size 109?

Is there a way to do that?

Answer 1

Add 2 to the chunk size when using it in the iteration.

chunk_size= 109
for i in range(0, len(ints), chunk_size+2):
    chunk = ints[i:i+chunk_size]

Answer 2

Use modular arithmetics:

blocksize = chuncksize + 2
newints = [i for i in ints if i%blocksize < chuncksize]

The other way is to loop backward:

blocksize = chuncksize + 2
for i in range(len(ints), 0, -blocksize)
    ints.pop(i+chuncksize)
    ints.pop(i+chuncksize+1)

Note: Did not test.