[英]Transform a JS array of strings into a union with IO-TS
I'm using io-ts and i'm wondering if there's a way to turn an array of strings (literals) into a union of such literals.我正在使用io-ts ,我想知道是否有办法将字符串(文字)数组转换为此类文字的联合。 For example:
例如:
export const CONTROLS = [
"section",
"text",
"richtext",
"number",
];
export const ControlType = t.union(
// What to do here? Is this even possible? This is what came to mind but it's obviously wrong.
// CONTROL_TYPES.map((type: string) => t.literal(type))
);
I don't know if this is possible but given that io-ts
is just JS functions I don't see why not.我不知道这是否可能,但鉴于
io-ts
只是 JS 函数,我不明白为什么不这样做。 I just don't know how.我只是不知道怎么做。
The end result in this case should be (with io-ts):在这种情况下,最终结果应该是(使用 io-ts):
export const ControlType = t.union(
t.literal("section"),
t.literal("text"),
t.literal("richtext"),
t.literal("number"),
);
io-ts formally recommends to use keyof
for better performance with string literal unions. io-ts 正式推荐使用
keyof
以获得更好的字符串文字联合性能。 Thankfully, that also makes this problem much easier to solve:值得庆幸的是,这也使这个问题更容易解决:
export const CONTROLS = [
"section",
"text",
"richtext",
"number",
] as const;
function keyObject<T extends readonly string[]>(arr: T): { [K in T[number]]: null } {
return Object.fromEntries(arr.map(v => [v, null])) as any
}
const ControlType = t.keyof(keyObject(CONTROLS))
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