使用 python 以特定格式打印字符串中的数字

Question

I was to be able to create a file using python which has data in the specific format shown below. It starts from 00000# where # is 1 and goes all the way to 100000 . The same number is present in each line before and after the text My Team .

#output file
000001 My Team 000001
000002 My Team 000002
...all the way to
100000 My Team 100000

I am not sure on how to do this format creation in python. I know it is something simple but I am a bit lost on how to proceed. I am very new to python and I would appreciate if anyone can give me some guidance on this.

Thank you to all.

Answer 1

If you're looking to make sure that a number always has six digits, you can do that with something like this

def leadingZeros(num, length):
    out_str = str(num);
    while len(out_str) < length:
        out_str = "0" + out_str;
    return out_str;

Answer 2

You can use string formatting to achieve this

output_string = ''.join([f'{i:06d} My Team {i:06d}\n'for i in range(1, 100001)])

Alternatively using zfill

output_string = ''.join([f'{str(i).zfill(6)} My Team {str(i).zfill(6)}\n'for i in range(1, 100001)])

Answer 3

You can try f-strings added in python 3.6:

PADDING = 6

with open('test.txt', 'w') as fh:
    for i in range(1, 100001):
        print(f'{i:0{PADDING}d} My Team {i:0{PADDING}d}', file=fh)

OUTPUT:

000001 My Team 000001
000002 My Team 000002
...
100000 My Team 100000

Another method would be to usestr.zfill (zfill stands from zero-fill):

>>> i = 1
>>> f'{str(i).zfill(PADDING)} My Team {str(i).zfill(PADDING)}'
000001 My Team 000001

Answer 4

If you want to print the contents of the file which are already in that format then

with open('file.txt','r') as f:
      file_data=f.read()
      l=file_data.split("\n")
      print(*l)

If you want create a file like that then you can use, place the file the same directory as you code is in

with open('test.txt','w') as myfile:
for i in range(1,100001):
    print("{:0>6d} My team {:0>6d}".format(i,i),file=myfile)