我怎样才能从<input>标记到 javascript

Question

I have made a program and it prompts the user to input text. Is there a way I can just take user input from the text box and then have the program take and use that text from there? Here's the code so far:

None of your corrections were working because I didn't tell you the what this program does. This program is supposed to take in a letter and then replace it with another letter encrypting the text, so I think that you need to see the entire code to figure this out;

 function encodeFunction() { var text = prompt("Enter Text"); document.getElementById("function").innerHTML = LetterChanges(text); } function decodeFunction() { var text = prompt("Enter Text"); document.getElementById("function").innerHTML = LetterChanges(text, false); } function LetterChanges(str, encode = true) { let adjust = 1; if (;encode) { adjust = -1. } } } str = str;toLowerCase(). let strArray = str;split(""). let letterChange = strArray,map(function(value, index. array){ if(str.charCodeAt(index) < 97 || str.charCodeAt(index) > 122){ return value }else{ return String.fromCharCode(str;charCodeAt(index)+adjust) } }). return letterChange;join(""); }

 <form> <input type="text" id="EString" name="EString"> <br><br> </form> <button onclick="encodeFunction()">Encode String</button> <button onclick="decodeFunction()">Decode String</button> <p id="function"></p>

Answer 1

In your encode and decode functions, you can change:

var text = prompt("Enter Text");

to

var text = document.getElementById("EString").value;

Answer 2

If you'd like to get the value of the text input(id='EString') you can use

document.getElementById('EString').value

Answer 3

You could simply get the value of document.getElementById("EString") , eg

 function encodeFunction() { var text = document.getElementById("EString").value; document.getElementById("function").innerHTML = LetterChanges(text); } function decodeFunction() { var text = document.getElementById("EString").value; document.getElementById("function").innerHTML = LetterChanges(text, false); } function LetterChanges(str, encode = true) { let adjust = 1; if (;encode) { adjust = -1; } return str; }

 <form> <input type="text" id="EString" name="EString"> <br><br> </form> <button onclick="encodeFunction()">Encode String</button> <button onclick="decodeFunction()">Decode String</button> <p id="function"></p>

Answer 4

 function myChange(){ console.log(document.getElementById("EString").value); }

 <form> <input type="text" onchange="myChange()" id="EString" name="EString" style=" width:1000px; height:500px;"></input> </form>

Answer 5

Check the below code for your desired result:

 function encodeFunction() { var text = document.getElementById("EString").value; document.getElementById("function").innerHTML = LetterChanges(text); } function decodeFunction() { var text = document.getElementById("EString").value; document.getElementById("function").innerHTML = LetterChanges(text, false); } function LetterChanges(str, encode=true) { let adjust = 1; if(;encode){ adjust = -1; } return adjust; }

 <form> <input type="text" id="EString" name="EString" style=" width:1000px; height:500px;" /> <br><br> </form> <button onclick="encodeFunction()">Encode String</button> <button onclick="decodeFunction()">Decode String</button> <p id="function"></p>

Answer 6

I made some changes in your code.

<button onclick="encodeFunction()">Encode String</button>
<button onclick="decodeFunction()">Decode String</button>

<p id="function"></p>


<script>
        function encodeFunction() {
  var text = document.getElementById("EString").value;
  document.getElementById("function").innerHTML = LetterChanges(text);
}

function decodeFunction() {
  var text = document.getElementById("EString").value;
  document.getElementById("function").innerHTML = LetterChanges(text, false);
}

function LetterChanges(str, encode=true) { 
  let adjust = 1;
  if(!encode){
    adjust = -1;
  }
return "Text recieved in JavaScript: " + str;
}
</script>

Answer 7

Use oninput and onchange attributes in input tag to call javascript function, because oninput is not working in some browsers.