C 程序运行一个额外的循环

Question

Write a program that points to the table of values of a given function. The initial value of x changes with step d, until the value of y (which is function of x) become greater than a number c

I have been trying to solve this task for some time but I always come across the same problem. The program always throws me one more value. See code. Thanks in advance.

#include <stdio.h>
#include <math.h>

main(){
    float x,d,y=0;
    float c;
    printf("Write begin and end of interval: ");
    scanf("%f%f",&x,&c);
    printf("Write step d: ");
    scanf("%f",&d);
    printf("x         y\n");
    while (c>y){
        y=pow(x,2)+(1/sqrt(x+1));
        printf("%.2f   %.2f\n",x,y);
        x+=d;
    }
}

This is what program does

Write begin and end of interval: 1 5
Write step d: 0.5
x         y
1.00   1.71
1.50   2.88
2.00   4.58
2.50   6.78  -------> this is undesired because y>c

Mathematical expression

Answer 1

Just add an if statement that checks for y after calculation. Note that you have to change it to c<=y if you don't want y=c to also not get printed.

#include <stdio.h>
#include <math.h>
int main(){
    float x,d,y=0;
    float c;
    printf("Write begin and end of interval: ");
    scanf("%f%f",&x,&c);
    printf("Write step d: ");
    scanf("%f",&d);
    printf("x         y\n");
    while (c>y){
        y=pow(x,2)+(1/sqrt(x+1));
        if(c<y){
            break;
        }
        printf("%.2f   %.2f\n",x,y);
        x+=d;
    }
}