通过提取名称中的整数对数组进行数字排序

Question

$Folders = Get-ChildItem -LiteralPath $PSScriptRoot | Where-Object {$_.PSIsContainer} | Select-Object -ExpandProperty BaseName

I get the output

Set 1
Set 10
Set 11 - A Memo
Set 2
Set 20
Set 22 - A Memo With Numbers 1234
Set 3
Set 33 - A Memo
...

$Folders = $Folders | Sort-Object {[INT]($_ -Replace 'Set ', '')} will sort the names in the right order but doesn't work if there is anything after the number like ' - A Memo'.

I've tried \b\d+\b on https://regexr.com but don't know how to implement that in this case. I need a regex that can extract the number after 'Set ' and discard everything else.

RegEx is a whole other language in itself

Answer 1

$names = @"
Set 1
Set 10
Set 11 - A Memo
Set 2
Set 20
Set 22 - A Memo With Numbers 1234
Set 3
Set 33 - A Memo
"@ -split "`n"

$names | sort @{expression={[int]($_ -replace '^\w+\s|\s.+')}}

You can use an expression with Sort-Object . Above this is done to replace everything you don't care about and convert to int for number sorting (in text sorting 1, 10, 11, 2, 20... is expected.)

Regex breakdown

^  - start of the string
\w - word character (matches S)
+  - the previous thing as many times as need (matches Se, Set, Seet, Seeeeeeeet)
\s - space
|  - or. so either everything before this, or everything after
\s - space
.  - any character
+  - I think this one's covered above

Note: + matches 1 or more. Use * if you need to match 0 or more.

Edit: As per zett42's helpful comment, you could use [int]($_ -split ' ')[1] in the Sort-Object expression. This splits your name into an array, and takes the 2nd element of that array.

Answer 2

Some alternatives for extracting the number, complementing g.sulman 's excellent answer .

First the most simplest method, assuming "Set" and the number are always separated by space:

$Folders | Sort-Object { [int]($_ -split ' ')[1] }

This uses the -split operator to split the string on space character, which returns an array. Then it converts the 2nd element to int .

---

Use -match operator:

$Folders | Sort-Object { [int]( $_ -match '\d+' ? $matches[0] : 0 ) }

Note that conditional operator ? requires PS 7. Alternative for older PS versions:

$Folders | Sort-Object { [int]( if( $_ -match '\d+' ){ $matches[0] } else { 0 } ) }

The -match operator finds the first sub string that matches the RegEx \d+ which stands for one or more digits. The found sub string can be accessed through $matches[0] .

---

Use Select-String cmdlet:

$Folders | Sort-Object { [int] ( $_ | Select-String -Pattern \d+ ).Matches[0].Value }

Same principle as the -match method. Just a different way to access the found sub string.