如何打印字符串中的所有内容，直到 python 中的第一个数字？

Question

I have an input file containing lines like the following:

"Kansas City Chiefs 42"

Each line contains a random number of spaces between the words and the numbers. I am trying to identify a way that I can slice the two values (word portion and number portion). My ideal output would be:

"Kansas City Chiefs"

"42"

Any ideas?

Answer 1

Checkout this regex:

import re

your_string = "Kansas City Chiefs 42"
items = re.split(r'\s+(?=\d)|(?<=\d)\s+', your_string)

print(items)

you got:

['Kansas City Chiefs', '42']

Answer 2

If your requirement is to read split as soon as you get the first number then below should work.

st = "Kansas City Chiefs 42"
text_part = ""

for each in st:
    if each.isnumeric():
        break
    text_part += each
number_part = st.replace(text_part, "")
print(text_part)
print(number_part)

you can you.strip() on either of the values depending on whether you want to keep the spaces at the end or not

Answer 3

Here's my implementation:

from nltk import word_tokenize

sentence = "Kansas City Chiefs 42"
tokens = word_tokenize(sentence)
word_phrases = " ".join([token for token in tokens if not token.isnumeric()])
numeric_phrase = " ".join([token for token in tokens if token.isnumeric()])
print(word_phrases)
print(numeric_phrase)

Answer 4

Answer

# Python3 program to extract all the numbers from a string 
import re 
  
# Function to extract all the numbers from the given string 
def getNumbers(str): 
    array = re.findall(r'[0-9]+', str) 
    return array 
  
# Driver code 
str = "adbv345hj43hvb42"
array = getNumbers(str) 
print(*array) 

Output:

345 43 42

Answer 5

You can use regex in python.

import re
def getNumber(str):
  arr = re.findall(r'[0-9]+', str)
str1 = "Kansas City Chiefs 42"
numbers = getNumber(str1)
str_val = str1[str1.find(numbers[0]):] # Kansas City Chiefs 
print(" ".join(numbers))
# output -> 42