[英]How to add pagination during filtered in django
my url appear like this '''http://127.0.0.1:8000/menu/?[%27tags%27,%20%271%27]&page=2'''我的 url 看起来像这样 '''http://127.0.0.1:8000/menu/?[%27tags%27,%20%271%27]&page=2'''
I want to make 'http://127.0.0.1:8000/menu/?tags=2&page=2'我想做'http://127.0.0.1:8000/menu/?tags=2&page=2'
Thank you all..谢谢你们..
munu_extras.py munu_extras.py
from django import template
from ..models import Menu
register = template.Library()
@register.simple_tag
def my_url(value,field_name,urlencode=None):
url = "{}={}".format(field_name,value )
if urlencode:
querystring = urlencode.split('=')
filtered_querystring = filter(lambda p: p.split('=')[0]!=field_name, querystring)
print(filtered_querystring)
encode_querystring = '='.join(filtered_querystring)
url = '?{}&{}'.format(querystring,url)
return url
In My menu.html在我的菜单中。html
{% if menus.has_previous %}
<a href="{% my_url 1 'page' request.GET.urlencode %}"><<<</a>
<a href="{% my_url menus.previous_page_number 'page' request.GET.urlencode %}"><<</a>
{% endif %}
{% if menus.has_next %}
<a href="{% my_url menus.next_page_number 'page' request.GET.urlencode %}">>></a>
<a href="{% my_url menus.paginator.num_pages 'page' request.GET.urlencode %}">>>></a>
{% endif %}
You need to use request.GET
.您需要使用request.GET
。 So when you enter the url http://127.0.0.1:8000/menu/?tags=2&page=2
.所以当你输入 url http://127.0.0.1:8000/menu/?tags=2&page=2
时。 The part after the ?
后面的部分?
will be resulted in request.GET
.将导致request.GET
。 Suppose, if your urls.py
, you have a url: path('menu',views.function,name='function')
and in views.py
you have a function:假设,如果你的urls.py
,你有一个 url: path('menu',views.function,name='function')
并且在views.py
你有一个 ZC1C425268E68384FAB11
def function(request):
print(request.GET)
return HttpResponse('success')
In the print statement output, it will be a dictionary with keys tags
and page
with values 2
and 2
respectively在打印语句 output 中,它将是带有键tags
的字典和分别具有值2
和2
的page
You are splitting the url-encoded GET parameters on =
instead of &
, and various similar mistakes.您将 url 编码的 GET 参数拆分为=
而不是&
,以及各种类似的错误。
@register.simple_tag
def my_url(value, field_name, urlencode=None):
url = "?{}={}".format(field_name, value)
if urlencode:
querystring = urlencode.split('&')
filtered_querystring = filter(lambda p: p.split('=')[0] != field_name, querystring)
encoded_querystring = '&'.join(filtered_querystring)
url = '{}&{}'.format(url, encoded_querystring)
return url
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