将 Class 拆分为 Lambda 中的属性 Java 中的表达式

Question

Let's say you have a custom class:

public class T {
    int a;
    int b;
}

Is there a way you can split up the class in a lambda expression in the following way:

(Stream of T instances).forEach((a, b) -> {});

Answer 1

Java doesn't have the concept of tuples, so no! But there can be a workaround by converting the stream to a Map ( which has a lot of limitations and consequences ):

(Stream of T instances)
    .collect(Collectors.toMap(t -> t.a, t -> t.b))
    .forEach((a, b) -> {});