我正在编码 Arduino，但我对将 2 个传感器和 1 个伺服与按钮结合起来感到困惑

Question

I'm coding Arduino, but I'm confused about combining 2 sensors and 1 servo with a push button. I hope someone can help me.

I have made one by one the sensor coding and it works, but I want to combine them into one program.

// code void loop water temperatur sensor       
void loop(void`{ 
  sensors.requestTemperatures(); 
  Celcius = sensors.getTempCByIndex(0);
  Serial.print(Celcius);
  Serial.println(" C ");
  delay(1000);
}

// this code push button with servo
// code void servo with push button
void loop() {
  if (digitalRead(pushButtonPin) == LOW) {
    buttonPushed = 1;
    Serial.println("Servo ON");
    delay(1000);
  }
  if (buttonPushed) {
    // change the angle for next time through the loop:
    angle = angle + angleStep;
         
    // reverse the direction of the moving at the ends of the angle:
    if (angle >= maxAngle) {
      angleStep = -angleStep;
      if (type == 1) {
        buttonPushed =0;                   
      }
    }
             
    if (angle <= minAngle) {
      angleStep = -angleStep;
      if (type == 2) {
        buttonPushed =0;       
      }
    }
            
    myservo.write(angle); // move the servo to desired angle 
    delay(100); // waits for the servo to get there
  }
}

// Ph Sensor code
void loop(void) {
  static unsigned long samplingTime = millis();
  static unsigned long printTime = millis();
  static float pHValue, voltage;
  if (millis() - samplingTime > samplingInterval) {
    pHArray[pHArrayIndex++] = analogRead(SensorPin);
    if (pHArrayIndex==ArrayLenth)
      pHArrayIndex=0;
    voltage = avergearray(pHArray, ArrayLenth) * 5.0 / 1024;
    pHValue = 3 * voltage + Offset;
    samplingTime=millis();
  }
  if (millis() - printTime > printInterval) { //Every 800 milliseconds, print a numerical, convert the state of the LED indicator
    Serial.print("Voltage:");
    Serial.print(voltage, 2);
    Serial.print("    pH value: ");
    Serial.println(pHValue, 2);
    digitalWrite(LED, digitalRead(LED) ^ 1);
    printTime = millis();
  }
}

double avergearray(int* arr, int number){
  int i;
  int max, min;
  double avg;
  long amount = 0;
  if (number <= 0) {
    Serial.println("Error number for the array to avraging!/n");
    return 0;
  }
  if (number<5) { //less than 5, calculated directly statistics
    for (i=0; i<number; i++) {
      amount += arr[i];
    }
    avg = amount / number;
    return avg;
  } else {
    if (arr[0] < arr[1]) {
      min = arr[0];
      max = arr[1];
    } else {
      min = arr[1];
      max = arr[0];
    }
    for (i=2; i<number; i++) {
      if (arr[i] < min) {
        amount += min; //arr<min
        min = arr[i];
      } else {
        if (arr[i] > max) {
          amount += max; //arr>max
          max = arr[i];
        } else {
          amount += arr[i]; //min<=arr<=max
        }
      } //if
    } //for
    avg = (double)amount / (number - 2);
  } //if
  return avg;
}

Answer 1

Your " Ph Sensor code " demonstrates how to do 2 things at different time intervals in one loop.

void loop() {
    if (/* time is right to do thing 1 */) {
         // do thing 1
    }
    if (/* time is right to do thing 2 */) {
         // do thing 2
    }
}

This is called a state machine . You can extend this logic to do 4 or more things in one loop.

Obviously you can't use delay as it blocks the entire loop, preventing other work from continuing. So you need to convert the first two loops into the structure similar to the one above. Then you will be able to merge all the loops into a single one.