知道如何在 linux 和 shell 脚本中使用带条件的超时命令

Question

aim working on some shell script, i would like to check the following command

df -h

if timeout more than 60 second then echo "error " else pass.

so if this command will not responding for 1 minute then I will receive and error message, otherwise it will pass, any creative idea will be high apricated.

Answer 1

timeout 60 df -h > /dev/null && echo "PASS" || echo "PROBLEM"

Using timeout, if the command df -h doesn't execute within 60 seconds or errors, it will return a none 0 return code. If a none 0 return code is returned echo "PROBLEM" using the || condition.