[英]Bash - Parse environment variables in bash function
I have a bash function that retrieves environment variables from a .env
file.我有一个 bash function 从.env
文件中检索环境变量。
In my .env
file I have the following variables在我的.env
文件中,我有以下变量
USER=luis
IMAGE_NAME=application
IMAGE_VERSION=latest
IMAGE_TAG=${USER}/${IMAGE_NAME}:${IMAGE_VERSION}
In my bash script I have my env function在我的 bash 脚本中,我有我的环境 function
function dotenv::get() {
variable=$(grep ^"${1}"= "$(pwd)/.env" | xargs)
IFS="=" read -ra variable <<< "${variable}"
echo "${variable[1]}"
}
When I execute dotenv::get IMAGE_TAG
.当我执行dotenv::get IMAGE_TAG
时。
Expected result: luis/application:latest
预期结果: luis/application:latest
Current result: ${USER}/${IMAGE_NAME}:${IMAGE_VERSION}
当前结果: ${USER}/${IMAGE_NAME}:${IMAGE_VERSION}
I'm aware my function is incomplete, however I'm not sure what are the next steps to achieve my objective.我知道我的 function 不完整,但是我不确定实现我的目标的下一步是什么。
The file looks like it wants to keep shell-ish syntax.该文件看起来想要保留 shell-ish 语法。 If so, just source
it:如果是这样,只需source
它:
. ./.env
echo "$IMAGE_TAG"
dotenv::get() {
. ./.env;
echo "${!1}"
}
If this is not your intention, then implement a whole parser of variables from a file with a ${...}
variable substitution of already set variables.如果这不是您的意图,则使用${...}
变量替换已设置变量的文件实现整个变量解析器。
You are still missing two things: interpreting your variable assignments, and interpreting the content of the variable you query:您仍然缺少两件事:解释您的变量分配,并解释您查询的变量的内容:
. $(pwd)/.env # source the environment file so that variables are assigned
function dotenv::get() {
variable=$(grep ^"${1}"= "$(pwd)/.env" | xargs)
IFS="=" read -ra variable <<< "${variable}"
eval X=${variable[1]} # interpret the expression containing variables
echo $X
}
dotenv::get IMAGE_TAG
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